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Topic 2/3
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Chlorine ($Cl_2$) exhibits the unique ability to undergo disproportionation when reacting with aqueous sodium hydroxide ($NaOH$). Disproportionation is a type of redox reaction where a single element undergoes both oxidation and reduction simultaneously. In the case of chlorine, it is both reduced to chloride ions ($Cl^-$) and oxidized to hypochlorite ($ClO^-$) under cold conditions, and to chlorate ions ($ClO_3^-$) under hot conditions.
At lower temperatures, the reaction between chlorine and aqueous sodium hydroxide predominantly yields sodium chloride ($NaCl$) and sodium hypochlorite ($NaClO$). The balanced chemical equation for this reaction is: $$Cl_2 + 2NaOH \rightarrow NaCl + NaClO + H_2O$$
This reaction is exothermic but controlled at lower temperatures to favor the formation of hypochlorite ions without proceeding further to chlorate formation. Sodium hypochlorite is commonly known for its use in household bleach and disinfectants.
Upon increasing the temperature, the reaction kinetics change, leading to the production of sodium chlorate ($NaClO_3$) in addition to sodium chloride. The balanced chemical equation for the hot reaction is: $$3Cl_2 + 6NaOH \rightarrow 5NaCl + NaClO_3 + 3H_2O$$
The elevated temperature facilitates the further oxidation of hypochlorite ions to chlorate ions, thereby altering the product distribution. Sodium chlorate is widely used in the production of herbicides and as an oxidizing agent in various industrial processes.
The reaction mechanism involves the initial attack of hydroxide ions on the chlorine molecule, leading to the formation of intermediate species that either retain or alter the oxidation state of chlorine. In cold conditions, the pathway favors the formation of hypochlorite, while heat directs the reaction towards chlorate formation. The following steps outline the general mechanism:
Understanding the stoichiometry is crucial for predicting the amounts of reactants and products involved. For the cold reaction: $$Cl_2 + 2NaOH \rightarrow NaCl + NaClO + H_2O$$ - 1 mole of chlorine reacts with 2 moles of sodium hydroxide to produce 1 mole of sodium chloride and 1 mole of sodium hypochlorite. For the hot reaction: $$3Cl_2 + 6NaOH \rightarrow 5NaCl + NaClO_3 + 3H_2O$$ - 3 moles of chlorine react with 6 moles of sodium hydroxide to yield 5 moles of sodium chloride and 1 mole of sodium chlorate.
The products of chlorine's reaction with aqueous sodium hydroxide have diverse applications:
The reactions of chlorine with aqueous sodium hydroxide are governed by thermodynamic principles. The spontaneity and favorability of product formation can be analyzed using Gibbs free energy ($\Delta G$). At lower temperatures, the formation of hypochlorite is more favorable, whereas higher temperatures shift the equilibrium towards chlorate formation due to the exothermic nature of hypochlorite formation and the endothermic steps required for further oxidation to chlorate.
The relationship can be expressed as: $$\Delta G = \Delta H - T\Delta S$$ where $\Delta H$ is the enthalpy change, $T$ is the temperature, and $\Delta S$ is the entropy change. By manipulating temperature, the reaction pathways are controlled to favor desired products.
Beyond thermodynamics, kinetics plays a crucial role in determining the reaction outcome. The rate at which chlorine is consumed and products are formed depends on factors such as activation energy and the presence of catalysts. Higher temperatures not only favor the thermodynamic stability of chlorate ions but also provide the necessary energy to overcome activation barriers for the multi-step oxidation process.
Electrochemistry offers deeper insights into the redox processes occurring during the reaction. Chlorine undergoes both reduction and oxidation:
Understanding these half-reactions is essential for analyzing the electron transfer mechanisms and designing electrochemical cells for industrial chlorate production.
The production and use of chlorate and hypochlorite compounds have significant environmental implications. While sodium hypochlorite is effective for disinfection, its overuse can lead to the formation of harmful by-products such as chlorinated organic compounds. Sodium chlorate, being a potent herbicide, can impact non-target plant species and soil health if not managed properly. Sustainable practices and regulatory frameworks are essential to mitigate these environmental risks.
To quantitatively analyze the reactions, stoichiometric calculations are imperative. For instance, determining the amount of sodium hypochlorite produced from a given amount of chlorine requires the use of mole ratios derived from the balanced equations.
Example Calculation: If 5 moles of $Cl_2$ react with excess $NaOH$ under cold conditions, the moles of $NaClO$ produced can be calculated as: $$5 \text{ moles } Cl_2 \times \frac{1 \text{ mole } NaClO}{1 \text{ mole } Cl_2} = 5 \text{ moles } NaClO$$
Similarly, under hot conditions, 3 moles of $Cl_2$ yield 1 mole of $NaClO_3$. Thus, 9 moles of $Cl_2$ would produce 3 moles of $NaClO_3$.
The chemistry of chlorine and its reactions with bases intersects with various scientific disciplines:
Condition | Products | Balanced Equation |
Cold Aqueous NaOH | NaCl and NaClO | $Cl_2 + 2NaOH \rightarrow NaCl + NaClO + H_2O$ |
Hot Aqueous NaOH | NaCl and NaClO3 | $3Cl_2 + 6NaOH \rightarrow 5NaCl + NaClO_3 + 3H_2O$ |
To remember the products based on temperature, use the mnemonic “Cold Hypo, Hot Chloro”:
Did you know that the industrial production of sodium chlorate, a key product of chlorine reacting with hot aqueous sodium hydroxide, is a vital step in manufacturing herbicides like “Rodeo”? Additionally, sodium hypochlorite, produced under cold conditions, not only serves as household bleach but also plays a crucial role in wastewater treatment processes by effectively eliminating harmful bacteria and pathogens.
Students often confuse the products formed under different temperature conditions. For example, multiplying coefficients incorrectly when balancing the hot reaction can lead to the wrong stoichiometric ratios:
Incorrect: $Cl_2 + NaOH \rightarrow NaCl + NaClO_3 + H_2O$
Correct: $3Cl_2 + 6NaOH \rightarrow 5NaCl + NaClO_3 + 3H_2O$
Another common mistake is neglecting to account for the role of temperature in determining whether sodium hypochlorite or sodium chlorate is formed.