Choosing $u$ and $dv$ for Integration by Parts
Introduction
Integration by Parts is a fundamental technique in Calculus BC, particularly for solving integrals involving products of functions. Choosing the appropriate $u$ and $dv$ is crucial for simplifying the integral and obtaining a solution efficiently.
Key Concepts
Understanding Integration by Parts
Integration by Parts is derived from the product rule for differentiation. The formula is given by:
$$\int u \, dv = uv - \int v \, du$$
This formula allows for the integration of products of functions by identifying parts of the integrand as $u$ and $dv$, differentiating $u$ to find $du$, and integrating $dv$ to find $v$.
Choosing $u$ and $dv$
Choosing $u$ and $dv$ correctly is essential for simplifying the integral. A common mnemonic to aid in this selection is the LIATE rule, which prioritizes functions based on the category in which they fall.
- L - Logarithmic functions: Functions like $\ln(x)$, $\log(x)$
- I - Inverse trigonometric functions: Functions like $\arctan(x)$, $\arcsin(x)$
- A - Algebraic functions: Polynomials like $x^n$, where $n$ is a real number
- T - Trigonometric functions: Functions like $\sin(x)$, $\cos(x)$
- E - Exponential functions: Functions like $e^x$, $a^x$, where $a$ is a constant
According to LIATE, select $u$ from the function that appears first in the list. For example, given the integral $\int x e^x dx$, $u$ would be $x$ (an algebraic function) and $dv$ would be $e^x dx$ (an exponential function).
Procedure for Integration by Parts
- Identify $u$ and $dv$: Use the LIATE rule or other strategies to select $u$ and $dv$ such that differentiating $u$ and integrating $dv$ simplifies the integral.
- Differentiate and Integrate: Compute $du$ by differentiating $u$, and compute $v$ by integrating $dv$.
- Apply the Formula: Substitute $u$, $dv$, $v$, and $du$ into the Integration by Parts formula.
- Simplify and Integrate: Simplify the resulting integral. If necessary, apply Integration by Parts again.
Examples
Example 1: Compute $\int x e^x dx$.
Solution:
- Choose $u$ and $dv$: Let $u = x$ (algebraic), $dv = e^x dx$ (exponential).
- Differentiate and Integrate: $du = dx$, $v = e^x$.
- Apply the Formula:
$$\int x e^x dx = x e^x - \int e^x dx$$
$$= x e^x - e^x + C$$
$$= e^x (x - 1) + C$$
Example 2: Compute $\int \ln(x) dx$.
Solution:
- Choose $u$ and $dv$: Let $u = \ln(x)$ (logarithmic), $dv = dx$ (algebraic).
- Differentiate and Integrate: $du = \frac{1}{x} dx$, $v = x$.
- Apply the Formula:
$$\int \ln(x) dx = x \ln(x) - \int x \cdot \frac{1}{x} dx$$
$$= x \ln(x) - \int 1 dx$$
$$= x \ln(x) - x + C$$
Reduction of Integrals
Sometimes, applying Integration by Parts repeatedly can reduce an integral to a more manageable form. This is particularly useful for integrals that do not simplify after one application of the technique.
Tabular Integration by Parts
Tabular Integration is a streamlined method of applying Integration by Parts multiple times. It is especially effective when integrating the product of a polynomial and an exponential or trigonometric function.
- Create a table with derivatives of $u$ and integrals of $dv$.
- Alternate signs and multiply diagonally to sum the terms.
- Continue until the derivatives of $u$ are zero.
Example: Compute $\int x^2 e^x dx$ using Tabular Integration.
Solution:
Derivatives of $u$ |
Integrals of $dv$ |
$x^2$ |
$e^x$ |
$2x$ |
$e^x$ |
$2$ |
$e^x$ |
$0$ |
|
Now, apply the alternating signs:
$$
\int x^2 e^x dx = x^2 e^x - 2x e^x + 2 e^x + C = e^x (x^2 - 2x + 2) + C
$$
Comparison Table
Aspect |
Choosing $u$ |
Choosing $dv$ |
Definition |
The function to be differentiated to obtain $du$ |
The function to be integrated to obtain $v$ |
Selection Priority |
Higher in LIATE |
Lower in LIATE |
Purpose |
To simplify the integrand upon differentiation |
To provide an integrable component upon integration |
Pros |
Reduces complexity by differentiation |
Ensures $v$ is easily integrable |
Cons |
Incorrect choice can complicate the integral |
If $dv$ is not easily integrable, the method fails |
Summary and Key Takeaways
- Choosing appropriate $u$ and $dv$ is critical for effective Integration by Parts.
- The LIATE rule serves as a helpful guideline for selecting $u$ and $dv$.
- Proper application simplifies complex integrals, making them manageable.
- Tabular Integration can streamline the process, especially for higher-order polynomials.
- Practice is essential to master the selection and application of Integration by Parts.