Past Papers
Practice Questions: Cambridge IGCSE Mathematics - International - 0607 - Advanced Paper 4 2018 Summer Zone 3
Like Icon 0
Share
Questions: 7/12
Topic: CH7 - Mensuration
Solution
PRACTISE
Similar Questions
LEARN
Concepts with Sparky
Close Icon
Close Icon
Close Icon
Access AI-Features in
IB Past Papers App
Access
AI-Features in
IB Past Papers App
QR Code

Get exclusive access to our AI features such as instant feedback, similar questions and AI tutor sessions.

;

Related Questions from Similar Topic

Theory
CH7 - Mensuration
The diagram shows a shape made from a cylinder and a cone. The cylinder and cone have a common radius of 6 m. The height of the cylinder is 10 m and t...
2015 Summer
Theory
CH7 - Mensuration
The diagram shows a rectangle, two semicircles and two right-angled triangles.(a) Find the total area of the shape. Give your answer in the form $a + ...
2015 Summer
Theory
CH7 - Mensuration
(a) The diagram shows two similar triangles $EAB$ and $ECD$. $AB = 20 \text{ cm}$, $CD = 15 \text{ cm}$, $AC = 40 \text{ cm}$ and angle $CAB = 90^\c...
2015 Summer
Theory
CH7 - Mensuration
The diagram shows a solid cone inside a cylinder.The base radius of the cone and the radius of the cylinder are both 10 cm.The height of both the cone...
2015 Winter
Theory
CH7 - Mensuration
The area of a semicircle is $32\pi \text{cm}^2$.Work out the perimeter of the semicircle.Give your answer in terms of $\pi$..............................
2016 Summer
Theory
CH7 - Mensuration
The diagrams show a solid hemisphere and a solid cone.Both the hemisphere and the base of the cone have radius 9cm.The volumes of the two shapes are e...
2016 Winter
Theory
CH7 - Mensuration
A circle of radius 5 cm is inscribed inside a square. The square has one side on the base of an equilateral triangle, $ABC$. The other two vertices of...
2016 Winter
Theory
CH7 - Mensuration
A solid hemisphere has radius 6 cm.(a) Find, in terms of \( \pi \),(i) the volume of the hemisphere, .............................................. cm...
2016 Winter
Theory
CH7 - Mensuration
The diagram shows a solid, square-based pyramid $VABCD$. $O$ is the centre of the base $ABCD$ and $VO$ is perpendicular to the base.$N$ is the midpoin...
2016 Winter
Theory
CH7 - Mensuration
AD is an arc of a circle, centre C, and BCD is a straight line. $BC = 9 \text{ cm}$, $CD = 6 \text{ cm}$ and angle $ACD = 90^{\circ}$.Find the total a...
2017 Summer

More Questions from year 2018

Theory
CH1 - Number
(a) Work out $5 - 7 \times 2 + 8$.............................................. [1](b) Find $\sqrt[3]{0.001}$............................................
2018 Summer
Theory
CH5 - Geometry
(a) Find, by measuring, the size of this reflex angle. .........................................................[1](b) Work out the value of $x$. NOT...
2018 Summer
Theory
CH2 - Algebra
Solve these simultaneous equations. $x - 3y = 7$ $x - 2y = 5$ $x = \text{.................................}$ $y = \text{.................................
2018 Summer
Theory
CH1 - Number
(a) Write 0.68 as a fraction in its lowest terms......................................................... [1](b) Work out $\frac{3}{7} \cdot \frac{8}{...
2018 Summer
Theory
CH2 - Algebra
These are the first five terms of a sequence.1 \quad 0 \quad 1 \quad 4 \quad 9Find the $n^{th}$ term of this sequence.
2018 Summer
Theory
CH2 - Algebra
(a) Expand and simplify.$(2p - 7q)(p + q)$ ..................................................[2](b) Factorise.$2 - t - 2a + at$ .........................
2018 Summer
Theory
CH5 - Geometry
O is the centre of the circle.Find the value of $x$ and the value of $y$.$x = \text{.............................}$$y = \text{...........................
2018 Summer
Theory
CH2 - Algebra
y varies inversely as x^2. When x = 3, y = 4.Find y in terms of x.y = \text{.......................................} [2]
2018 Summer
Theory
CH2 - Algebra
(a) Find the value of $27^{\frac{2}{3}}$. [1](b) Simplify $18h^{18} \div 3h^{3}$. [2]
2018 Summer
Theory
CH2 - Algebra
Given the equation $v^2 = u^2 - 2as$, find $s$ in terms of $a$, $u$, and $v$.$s = \text{.....................................................} \,[2]$
2018 Summer