All Questions: AS & A Level Biology - 9700 Paper 4 2023 Summer Zone 3
Theory
MCQ
01.
Theory 9 Marks
CH12 - ENERGY AND RESPIRATION

(a) The Krebs cycle was named after the biochemist Sir Hans Krebs, who worked out the sequence in 1937.

Fig. 1.1 is an outline of the Krebs cycle.



Identify substances $P\text{--}U$.
P ...........................................................
Q ...........................................................
R ...........................................................
S ...........................................................
T ...........................................................
U ...........................................................
[3]

(b) Describe how ATP is produced from ADP in the Krebs cycle.
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[2]

(c) Describe \textbf{and} explain the features of ATP that make it suitable as the universal energy currency.
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[4]

02.
Theory 7 Marks
CH17 - SELECTION AND EVOLUTION

Humans use antibiotics to treat bacterial infections. The increased use of antibiotics has led to an increase in the number of strains of bacteria that are resistant to antibiotics.
The evolution of antibiotic resistance in bacteria has resulted from natural selection.
Outline how bacteria become resistant to antibiotics.

03.
Theory 13 Marks
CH16 - INHERITED CHANGE

(a) An example of control of gene expression in prokaryotes is regulation in the \textit{lac} operon.

The \textit{lac} operon is a length of DNA that is made up of different parts.

Fig. 3.1 shows a simple diagram representing the \textit{lacI} (regulatory) gene and the \textit{lac} operon.



(i) Outline the main features of the \textit{lac} operon.

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(ii) Explain the role of the \textit{lacI} gene in the regulation of the \textit{lac} operon.

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(b) The \textit{lac} operon codes for inducible enzymes. Repressible operons code for repressible enzymes.

Suggest and explain why it is an advantage to a prokaryote to have a repressible operon.

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04.
Theory 10 Marks
CH19 - GENETIC TECHNOLOGY

One cause of the genetic disease severe combined immunodeficiency (SCID) is a mutation in the ADA gene. This mutation results in a deficiency of the enzyme adenosine deaminase (ADA).

Although ADA is found throughout the body, it is especially active in lymphocytes. The absence of functional ADA causes the build-up of toxic metabolites that kill lymphocytes and damage organs.

Babies are often diagnosed with SCID by six months old. Treatment can greatly improve the life expectancy of children with SCID.

Some treatment options are available.
• Enzyme replacement therapy with recombinant human ADA made by genetically modified (GM) Escherichia coli. Weekly intra-muscular injections are given.
• Bone marrow transplant if a well-matched donor, such as a close relative, can be found.
• Gene therapy.

(a) Suggest and explain why it may be more appropriate to use enzyme replacement therapy to treat SCID instead of a bone marrow transplant.
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(b) Outline the procedure used for gene therapy treatment of a person with SCID.
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(c) Suggest the social and ethical implications of gene therapy for SCID that need to be considered before treatment is carried out.
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05.
Theory 13 Marks
CH16 - INHERITED CHANGE

(a) Table 5.2 shows the observed numbers obtained of each of the four different phenotypes for the F2 generation.

[Table_5.2]

Table 5.2 compares the observed numbers with the numbers that would be expected in the F2 generation for a normal dihybrid ratio. Calculate $\chi^2$ for the F2 generation by completing Table 5.2.

The formula for $\chi^2$ is:

$\chi^2 = \sum \frac{(O-E)^2}{E}$ [3]

(b) The critical value at $p = 0.05$ and 3 degrees of freedom is 7.815. Comment on whether the null hypothesis should be accepted or rejected.

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(c) To produce the F2 generation, red males with black spots, $X^RY^RBb$, were crossed with red females with black spots, $X^RX^rBb$. Complete the Punnett square in Fig. 5.1 to show the genotypes and phenotypes of the F2 generation.

• Use the symbols $X^R$, $X^r$ and $Y^R$ for the alleles of the gene that controls body colour.
• Use the symbols B and b for the alleles of the gene that controls whether black spots are present or not.

Some of Fig. 5.1 has been completed for you.

[Fig_5.1] [4]

(d) Explain why there are no white males or males that are white with black spots in the F2 generation.

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(e) In another cross, red males with the genotype $X^RY^Rbb$ were mated with white females with the genotype $X^rX^rbb$. All the male offspring were expected to be red and all the female offspring were expected to be white. The observed results showed that the offspring included two red females out of 253 and one white male out of 198.

Suggest an explanation for this unexpected result.

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06.
Theory 14 Marks
CH14 - HOMEOSTASIS

(a) Fig. 6.1 shows part of the Bowman's capsule of a kidney nephron.

Name structures A, B and C.
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(b) Fluid is forced into the Bowman's capsule by ultrafiltration to form the glomerular filtrate.
Describe the role of structure B in ultrafiltration.
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(c) The main component of the glomerular filtrate formed in the Bowman’s capsule is water. Most of this water is reabsorbed as the filtrate passes along the nephron.
• 180 dm3 of water forms part of the glomerular filtrate each day.
• 1.4 dm3 of water leaves the body in urine each day.
Calculate the percentage of water in the glomerular filtrate that is reabsorbed as the glomerular filtrate passes along the nephron.
Show your working and give your answer to one decimal place.
answer ............................................................... % [2]
(d) Describe how the action of antidiuretic hormone (ADH) on the cells of the collecting duct leads to the reabsorption of water in the glomerular filtrate.
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07.
Theory 8 Marks
CH15 - CONTROL AND CO-ORDINATION

(a) Sarcomeres are the functioning units of the myofibrils of the muscle fibres (muscle cells) of striated muscle.
The arrival of an action potential at the sarcoplasmic reticulum of a striated muscle fibre can lead to the shortening of a sarcomere. This shortening occurs by the sliding filament model.
Outline the sequence of events occurring after stimulation of the sarcoplasmic reticulum that results in the shortening of a sarcomere.
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(b) Scientists compared the diameter of samples of striated muscle fibres taken from young mice and adult mice.
The results are shown in Fig. 7.1.

With reference to Fig. 7.1:
• describe two differences between the muscle fibres of young mice and adult mice
• suggest how these differences may affect the sliding filament model.
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08.
Theory 12 Marks
CH13 - PHOTOSYNTHESIS

(a) Fig. 8.1 is a diagram of a chloroplast.

Fig. 8.1
Using the letters K-N, complete Table 8.1.
Each letter may be used once, more than once, or not at all.
Table 8.1

| high concentration of protons | .................... |
| location of photosynthetic pigments | .................... |
| site of light-independent stage | .................... |
| site of light-dependent stage | .................... |
[4]

(b) Chlorophyll a is the main photosynthetic pigment in plants.
Describe the role of other photosynthetic pigments found in plant chloroplasts.
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(c) The absorption of different wavelengths of light by chloroplast pigments can be represented by an absorption spectrum.
Fig. 8.2 is an absorption spectrum of an extract of chloroplast pigments and an absorption spectrum of whole chloroplasts.

Fig. 8.2
With reference to Fig. 8.2, describe the differences between the two spectra and suggest explanations for the differences.
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09.
Theory 8 Marks
CH15 - CONTROL AND CO-ORDINATION

(a) Dopamine is a neurotransmitter released in some synapses in the brain. The release and action of dopamine is similar to that of acetylcholine.
Fig. 9.1 is a diagram of a brain synapse where dopamine is the neurotransmitter.

(i) Describe how the release of dopamine from the presynaptic neurone can lead to an action potential in the postsynaptic neurone.
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(ii) In brain cells, the amino acid tyrosine is changed into DOPA, which then is converted to dopamine.
Name another compound in the body produced from DOPA.
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(b) In some brain synapses, the neurotransmitter gamma-aminobutyric acid (GABA) is released. This results in an influx of chloride ions into the postsynaptic neurone.
Suggest and explain whether an action potential would be generated in the postsynaptic neurone if GABA is released into a brain synapse.
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10.
Theory 9 Marks
CH18 - BIODIVERSITY, CLASSIFICATION AND CONSERVATION

(a) The moose, Alces alces, is a large member of the deer family. It lives in temperate forests in North America and northern Europe, where snow is present for large parts of the year.

Fig. 10.1 shows an adult male moose feeding in a lake.



The moose feeds on a plant in the lake called watermilfoil, Myriophyllum aquaticum.

The moose and the watermilfoil belong to the domain Eukarya, which includes the kingdoms Animalia and Plantae.

Describe the main differences between the kingdom Animalia and the kingdom Plantae.
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(b) Measurements of the surface temperature of land and oceans can be taken from locations around the world. The mean global surface temperature for land and ocean combined can be calculated for a fixed time period.

Scientists calculated:
• the mean global temperature for the twentieth century
• the mean global temperature for each decade (ten years) from 1880 to 2020.

The mean temperature for each decade was compared to the mean for the twentieth century. For each decade, the difference in temperature was calculated.

The calculated differences are shown in Fig. 10.2.



(i) Calculate the rate of increase in temperature per decade between 1980 and 2020.
Show your working.
Write your answer to two decimal places.

answer ............................. °C per decade [2]

(ii) Moose populations have decreased in North America since 1980.

Suggest and explain reasons for the decrease in moose populations.
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