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Topic 2/3
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A non-right triangle is any triangle that does not contain a right angle (90 degrees). These triangles can be categorized as acute (all angles less than 90 degrees), obtuse (one angle greater than 90 degrees), or scalene and isosceles based on their side lengths. Solving non-right triangles involves finding unknown sides or angles using trigonometric principles.
The Sine Rule, also known as the Law of Sines, establishes a relationship between the lengths of a triangle's sides and the sines of its opposite angles. It is particularly useful in solving triangles that do not contain a right angle.
The Sine Rule is expressed as: $$\frac{a}{\sin A} = \frac{b}{\sin B} = \frac{c}{\sin C}$$
Applications: The Sine Rule is typically used in two scenarios:
Example: Suppose we have a triangle with angles A = 30°, B = 45°, and side a = 10 units. To find side b:
Using the Sine Rule: $$\frac{10}{\sin 30°} = \frac{b}{\sin 45°}$$ $$\frac{10}{0.5} = \frac{b}{0.7071}$$ $$20 = \frac{b}{0.7071}$$ $$b = 20 \times 0.7071$$ $$b \approx 14.14 \text{ units}$$
The Cosine Rule, or Law of Cosines, connects the lengths of a triangle's sides with the cosine of one of its angles. This rule is particularly useful in solving triangles when certain combinations of sides and angles are known.
The Cosine Rule is given by: $$c^2 = a^2 + b^2 - 2ab \cos C$$
Applications: The Cosine Rule is applied in two main scenarios:
Example: Consider a triangle with sides a = 7 units, b = 10 units, and angle C = 60°. To find side c:
Using the Cosine Rule: $$c^2 = 7^2 + 10^2 - 2 \times 7 \times 10 \times \cos 60°$$ $$c^2 = 49 + 100 - 140 \times 0.5$$ $$c^2 = 149 - 70$$ $$c^2 = 79$$ $$c = \sqrt{79}$$ $$c \approx 8.89 \text{ units}$$
Calculating the area of a non-right triangle can be efficiently done using trigonometric formulas. One such method employs the formula involving two sides and the sine of the included angle.
The area Δ is given by: $$Δ = \frac{1}{2} a b \sin C$$
Example: Given a triangle with sides a = 5 units, b = 7 units, and included angle C = 45°, the area is calculated as:
$$Δ = \frac{1}{2} \times 5 \times 7 \times \sin 45°$$ $$Δ = \frac{1}{2} \times 35 \times 0.7071$$ $$Δ = 17.5 \times 0.7071$$ $$Δ \approx 12.37 \text{ square units}$$
To solve a non-right triangle means to find all its unknown sides and angles. Depending on the known information, either the Sine Rule or the Cosine Rule can be applied, or a combination of both.
Steps to Solve a Triangle:
Complex Example: Solve a triangle where a = 8 units, b = 6 units, and C = 50°.
Step 1: Identify Known Elements:
Step 3: Apply the Sine Rule to Find Angle A: $$\frac{8}{\sin A} = \frac{6}{\sin 50°}$$ $$\sin A = \frac{8 \times \sin 50°}{6}$$ $$\sin A = \frac{8 \times 0.7660}{6}$$ $$\sin A = \frac{6.128}{6}$$ $$\sin A \approx 1.0213$$
Since the sine of an angle cannot exceed 1, this indicates that no such triangle exists with the given dimensions. Therefore, the triangle is impossible under the provided conditions.
Alternate Scenario: If a = 7 units, b = 10 units, and C = 60°, as previously calculated, the Cosine Rule can be used to find side c ≈ 8.89 units.
The SSA (Side-Side-Angle) scenario using the Sine Rule can lead to the ambiguous case, where two different triangles might satisfy the given conditions. This occurs when:
Example: Given a = 10 units, c = 7 units, and A = 30°, find angle C.
Using the Sine Rule: $$\frac{10}{\sin 30°} = \frac{7}{\sin C}$$ $$\frac{10}{0.5} = \frac{7}{\sin C}$$ $$20 = \frac{7}{\sin C}$$ $$\sin C = \frac{7}{20}$$ $$\sin C = 0.35$$
This gives two possible angles for C:
Therefore, two different triangles satisfy the given conditions.
Trigonometric identities are essential tools in simplifying and solving problems involving non-right triangles. Key identities include:
Application Example: Proof that $\sin^2 A + \sin^2 B + \sin^2 C = 2 + 2 \cos A \cos B \cos C$ for any triangle ABC.
Starting with the angles in a triangle:
$$A + B + C = 180°$$
Express C as: $$C = 180° - A - B$$
Using the identity $\sin(180° - x) = \sin x$, we get: $$\sin C = \sin (A + B) = \sin A \cos B + \cos A \sin B$$
Squaring both sides: $$\sin^2 C = (\sin A \cos B + \cos A \sin B)^2$$ $$\sin^2 C = \sin^2 A \cos^2 B + 2 \sin A \cos B \cos A \sin B + \cos^2 A \sin^2 B$$
Adding $\sin^2 A + \sin^2 B + \sin^2 C$:
$$\sin^2 A + \sin^2 B + \sin^2 C = \sin^2 A + \sin^2 B + \sin^2 A \cos^2 B + 2 \sin A \cos B \cos A \sin B + \cos^2 A \sin^2 B$$ $$= \sin^2 A (1 + \cos^2 B) + \sin^2 B (1 + \cos^2 A) + 2 \sin A \cos B \cos A \sin B$$
Using the identity $\cos^2 x = 1 - \sin^2 x$, substitute:
$$= \sin^2 A (1 + 1 - \sin^2 B) + \sin^2 B (1 + 1 - \sin^2 A) + 2 \sin A \cos B \cos A \sin B$$ $$= \sin^2 A (2 - \sin^2 B) + \sin^2 B (2 - \sin^2 A) + 2 \sin A \cos B \cos A \sin B$$
Simplifying leads to: $$\sin^2 A + \sin^2 B + \sin^2 C = 2 + 2 \cos A \cos B \cos C$$
Aspect | Sine Rule (Law of Sines) | Cosine Rule (Law of Cosines) |
Primary Use | Finding unknown sides or angles in ASA or AAS and SSA situations. | Finding unknown sides or angles in SAS and SSS situations. |
Formula | $\frac{a}{\sin A} = \frac{b}{\sin B} = \frac{c}{\sin C}$ | $c^2 = a^2 + b^2 - 2ab \cos C$ |
Advantages | Simple and straightforward for certain triangle configurations. | Versatile; can handle a wider range of triangle types, including obtuse triangles. |
Limitations | Ambiguous in SSA cases; may result in zero, one, or two solutions. | More complex calculations; not necessary for ASA or AAS cases. |
Applications | Navigational calculations, determining distances and angles from given points. | Engineering design, calculating forces, and computer graphics. |
Remember the acronym "SAS" for the Cosine Rule and "ASA/AAS" for the Sine Rule to determine which formula to use. A helpful mnemonic is "CAO" (Cosine for Angle, Opposite side) to recall the Cosine Rule. Practice drawing sketches of triangles to visualize known and unknown elements, which can guide the choice of the appropriate rule. For exam success, always double-check angle sums and validate solutions within the context of the triangle.
The Sine and Cosine Rules aren't just academic tools—they're essential in real-world applications like navigation and engineering. For instance, sailors use the Sine Rule to determine their position at sea when only certain angles and distances are known. Additionally, architects rely on the Cosine Rule to calculate forces in structures, ensuring buildings are safe and stable.
Students often confuse when to apply the Sine Rule versus the Cosine Rule. For example, using the Sine Rule in an SSS scenario instead of the Cosine Rule can lead to incorrect results. Another frequent error is neglecting to check for the ambiguous case in SSA problems, which may result in missing a possible second solution. Additionally, misapplying angle measures in trigonometric calculations, such as not converting degrees to radians when necessary, can cause calculation errors.