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Topic 2/3
15 Flashcards in this deck.
Triangles are one of the most basic and important shapes in geometry. Solving a triangle involves finding all its unknown sides and angles when certain parts of it are known. Two primary criteria used for solving triangles are ASA (Angle-Side-Angle) and AAS (Angle-Angle-Side).
The ASA criterion states that if two angles and the side between them in one triangle are congruent to two angles and the corresponding side in another triangle, then the two triangles are congruent. This means all corresponding sides and angles are equal.
Formula and Equations:
Given two angles ($\alpha$, $\beta$) and the included side ($a$), the third angle ($\gamma$) can be found using:
$$\gamma = 180^\circ - (\alpha + \beta)$$
Once all angles are known, the Law of Sines can be applied to find the remaining sides:
$$\frac{a}{\sin(\alpha)} = \frac{b}{\sin(\beta)} = \frac{c}{\sin(\gamma)}$$
Example:
Given $\angle A = 50^\circ$, $\angle B = 60^\circ$, and side $AB = 7$ cm, find side $AC$.
First, find $\angle C$: $$\angle C = 180^\circ - (50^\circ + 60^\circ) = 70^\circ$$ Then, apply the Law of Sines: $$\frac{AC}{\sin(60^\circ)} = \frac{7}{\sin(70^\circ)}$$ $$AC = 7 \times \frac{\sin(60^\circ)}{\sin(70^\circ)} \approx 7 \times \frac{0.8660}{0.9397} \approx 6.45 \text{ cm}$$
The AAS criterion states that if two angles and a non-included side of one triangle are congruent to the corresponding two angles and side of another triangle, then the triangles are congruent. Similar to ASA, all parts of the triangle can be determined.
Formula and Equations:
Given two angles ($\alpha$, $\beta$) and a non-included side ($b$), find the third angle ($\gamma$):
$$\gamma = 180^\circ - (\alpha + \beta)$$
Then, use the Law of Sines:
$$\frac{a}{\sin(\alpha)} = \frac{b}{\sin(\beta)} = \frac{c}{\sin(\gamma)}$$
Example:
Given $\angle A = 45^\circ$, $\angle B = 75^\circ$, and side $BC = 10$ cm, find side $AB$.
First, find $\angle C$: $$\angle C = 180^\circ - (45^\circ + 75^\circ) = 60^\circ$$ Apply the Law of Sines: $$\frac{AB}{\sin(75^\circ)} = \frac{10}{\sin(60^\circ)}$$ $$AB = 10 \times \frac{\sin(75^\circ)}{\sin(60^\circ)} \approx 10 \times \frac{0.9659}{0.8660} \approx 11.15 \text{ cm}$$
Solving ASA and AAS situations involves a systematic approach:
Understanding ASA and AAS is crucial in various real-world contexts, such as:
For more complex problems, such as those involving non-Euclidean geometry or three-dimensional spaces, additional trigonometric laws and principles may be required. However, mastery of ASA and AAS provides a solid foundation for these advanced topics.
Problem 1:
In triangle $ABC$, $\angle A = 30^\circ$, $\angle B = 45^\circ$, and side $AB = 8$ cm. Find the length of side $AC$.
Solution:
First, find $\angle C$:
$$\angle C = 180^\circ - (30^\circ + 45^\circ) = 105^\circ$$
Apply the Law of Sines:
$$\frac{AC}{\sin(45^\circ)} = \frac{8}{\sin(105^\circ)}$$
$$AC = 8 \times \frac{\sin(45^\circ)}{\sin(105^\circ)} \approx 8 \times \frac{0.7071}{0.9659} \approx 5.84 \text{ cm}$$
Problem 2:
Given triangle $DEF$ with $\angle D = 60^\circ$, $\angle E = 50^\circ$, and side $EF = 12$ cm, determine the length of side $DF$.
Solution:
First, find $\angle F$:
$$\angle F = 180^\circ - (60^\circ + 50^\circ) = 70^\circ$$
Apply the Law of Sines:
$$\frac{DF}{\sin(50^\circ)} = \frac{12}{\sin(70^\circ)}$$
$$DF = 12 \times \frac{\sin(50^\circ)}{\sin(70^\circ)} \approx 12 \times \frac{0.7660}{0.9397} \approx 9.79 \text{ cm}$$
Aspect | ASA (Angle-Side-Angle) | AAS (Angle-Angle-Side) |
---|---|---|
Definition | Two angles and the included side are known. | Two angles and a non-included side are known. |
Conditions | The known side is between the two known angles. | The known side is not between the two known angles. |
Application | Used when the side between two angles is known. | Used when a side not between two angles is known. |
Equations Used | Law of Sines and angle sum property. | Law of Sines and angle sum property. |
Pros | Direct approach when the included side is known. | Flexible use with non-included side information. |
Cons | Limited to scenarios where the included side is known. | May require additional steps if side is not clearly positioned. |
Mnemonic for Angle Sum: Remember "All Stars Align" to recall that the sum of angles in a triangle is always $180^\circ$.
Check Your Work: Always verify that the calculated angles sum up to $180^\circ$ and that sides satisfy the triangle inequality theorem to ensure accuracy.
The principles of ASA and AAS aren't just confined to textbooks! For instance, in surveying, these criteria help determine land boundaries with precision. Additionally, ancient architects used similar trigonometric methods to design iconic structures like the pyramids, ensuring their stability and symmetry.
Incorrect Angle Sum: Students often forget that the sum of angles in a triangle is $180^\circ$, leading to wrong calculations of the third angle.
Misapplying the Law of Sines: Confusing which sides correspond to which angles can result in inaccurate side lengths. For example, using the side opposite the wrong angle in the ratio.