No questions found
Work out.
$1 + 2 - 3 \times 4 \; \; \text{..................} \; [1]$
580
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523
Simplify fully.
$$\frac{5x}{12} \times \frac{4}{15x}$$
570
539
519
Solve.
$-3(1 - 4x) = 9$
$x = \text{...............................................}$ [3]
586
571
596
Divide 120 in the ratio 3:5.
.........................., .......................... [2]
516
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511
The mean of 5 numbers is 12. The mean of 3 of these numbers is 8.
Find the mean of the other two numbers.
591
588
525
y varies inversely as x.
When $x = 3$, $y = 16$.
Find $x$ when $y = 6$.
$x = \text{.................................}$ [3]
519
547
558
a = \begin{pmatrix} -4 \\ -3 \end{pmatrix} \quad b = \begin{pmatrix} 2 \\ -1 \end{pmatrix}
(a) Find \ a - 3b. \qquad \phantom{} [2]
(b) Find the magnitude of \ \begin{pmatrix} -4 \\ -3 \end{pmatrix}. \qquad \phantom{} [2]
528
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534
A shop has a sale and all prices are reduced by 20%.
(a) The original price of a shirt is $16.
Find the sale price of the shirt.
$\text{.................................} \ [2]
(b) The sale price of a dress is $40.
Find the original price of the dress.
$\text{.................................} \ [2]
580
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599
Factorise.
(a) $8x + 14$ .......................................................... [1]
(b) $8ax^2 - 6bx^3$ .......................................... [2]
(c) $6ax + 9ay - 8bx - 12by$ .................................. [2]
572
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572
The table shows the marks of 80 students in an examination.
[Table_1]
(a) On the grid, draw a cumulative frequency curve to show this information.
(Marks: 4)
(b) Use your graph to estimate the median mark of the students.
(Marks: 1)
522
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529
A is the point $(1, 7)$ and B is the point $(4, 1)$.
Find the equation of the perpendicular bisector of $AB$ in the form $y = mx + c$.
$y = \text{................................................}$
518
527
561
