All Questions: Cambridge IGCSE Mathematics - International - 0607 - Core Paper 5 2019 Winter Zone 1
Theory
MCQ
01.
Theory 8 Marks
CH1 - Number

(a) (i) Complete these equivalent fractions.

$ \frac{1}{2} = \frac{5}{10}, \quad \frac{1}{5} = \frac{2}{10}, \quad \frac{7}{20} = \frac{\text{______}}{100}, \quad \frac{1}{25} = \frac{\text{______}}{100}, \quad \frac{3}{500} = \frac{\text{______}}{1000} $

(a) (ii) The denominators of the equivalent fractions in part (i) are 10, 100 and 1000. The smallest prime number is 2.
Put a prime number in each box to complete these statements.

$10 = $ $ = 2 \times 5 $
$100 = 10 \times 10 = 2 \times 5 \times \text{______} \times \text{______}$
$1000 = 10 \times 10 \times 10 = 2 \times 5 \times \text{______} \times \text{______} \times \text{______}$

(a) (iii) Complete the table.

| Fraction | $\frac{1}{2}$ | $\frac{1}{5}$ | $\frac{7}{20}$ | $\frac{1}{25}$ | $\frac{3}{500}$ |
| -------- | ------- | ------- | -------- | ------- | -------- |
| Decimal | 0.5 | 0.2 | | | |

(a) (iv) Write down a different fraction with a numerator of 1 and a denominator between 30 and 99 which can be written as a terminating decimal.

(b) (i) Put a prime number in each box to complete these statements.

$20 = 2 \times 2 \times 5$
$25 = 5 \times 5$
$50 = 2 \times \text{______} \times 5$
$100 = \text{______} \times 5 \times 5$
$500 = 2 \times 2 \times \text{______} \times \text{______} \times \text{______}$

(b) (ii) Use your answers to part (i) to help you complete the table.

| Fraction | Decimal | Number of decimal places | Denominator written as a product of primes using powers | Larger power |
| -------- | ------- | ------------------------ | ---------------------------------------------------- | ------------ |
| $\frac{1}{20}$ | 0.05 | 2 | $2^{2} \times 5$ | 2 |
| $\frac{7}{25}$ | 0.28 | 2 | $5^{2}$ | 2 |
| $\frac{9}{50}$ | 0.18 | 2 | | 2 |
| $\frac{19}{100}$ | 0.19 | | | |
| $\frac{13}{200}$ | 0.065 | 3 | $2^{3} \times 5^{2}$ | 3 |
| $\frac{11}{500}$ | 0.022 | | | |
| $\frac{17}{5000}$ | 0.0034| | $2^{3} \times 5^{4}$ | 4 |

(b) (iii) A fraction has a numerator of 1 and a denominator of $2^{14} \times 5^{7}$.
Write down the number of decimal places in the decimal form of this fraction.

(b) (iv) The denominator of a fraction that can be written as a terminating decimal only has one or two possible prime factors.
Write down these prime factors.

02.
Theory 9 Marks
CH1 - Number

This question is about repeating decimals. The number of digits in the repeating pattern is called the repeat length.
Example
$\frac{1}{13} = 0.076923\, 076923\, 076923\ldots = \underline{0.076\, 923}$ This is a repeating decimal with a repeat length of 6.
(a)
(i) Complete these equivalent fractions.
$\frac{1}{3} = \frac{1}{9} \quad \frac{1}{11} = \frac{1}{99} \quad \frac{1}{37} = \frac{1}{999} \quad \frac{1}{111} = \frac{1}{999} \quad \frac{1}{41} = \frac{1}{99\,999} \quad \frac{1}{7} = \frac{1}{999\,999}$
(ii) Complete the table.
[Table_1]
(iii) Use your answers to part (i) and part (ii) to help you complete the table.
[Table_2]
(iv) Give an example of a fraction with a numerator of 1 which can be written as a repeating decimal with a repeat length of 9.
...............................................................
(v) A repeating decimal has a repeat length of $k$.
Write down an expression, in terms of $k$, for the denominator of this fraction.
...............................................................
(b)
(i) $\frac{1}{407} = \frac{1}{11 \times 37} = \frac{1}{11} \times \frac{1}{37}$
$\frac{1}{407}$ is changed to its decimal form.
Show that this has a repeat length that is equal to the lowest common multiple (LCM) of the repeat lengths of the decimal forms of $\frac{1}{11}$ and $\frac{1}{37}$.
...............................................................
(ii) Show how the lowest common multiple (LCM) of the repeat lengths of $\frac{1}{7}$ and $\frac{1}{37}$ gives the repeat length of $\frac{1}{259}$.
...............................................................

03.
Theory 10 Marks
CH1 - Number

Some decimals have non-repeating decimal parts followed by repeating decimal parts.
Example
$$0.6\overline{5} = 0.65555\ldots$$
In this decimal, the 6 does not repeat but the 5 does.
(a) Show that adding the decimal forms of $\frac{1}{5}$ and $\frac{1}{3}$ gives a decimal of this type.

(b) Complete the table.

[Table_1]

FractionDecimalNumber of non-repeating decimal placesRepeat lengthDenominator written as a product of primes using powers
$\frac{1}{6}$$0.1\overline{6}$11$2 \times 3$
$\frac{1}{12}$$0.08\overline{3}$21
$\frac{7}{75}$
$\frac{11}{24}$3
$\frac{317}{600}$$0.528\overline{3}$$2^3 \times 5^2 \times 3$
$\frac{1}{1320}$$0.000\overline{75}$32$2^3 \times 5 \times 11 \times 3$
$\frac{50001}{101750}$$0.491\overline{410319}$36$2 \times 5^3 \times 11 \times 37$

(c) A fraction of the form $\frac{1}{2^a \times 5^b \times c \times d}$ where $a$ and $b$ are positive integers and $c$ and $d$ are different primes is changed to its decimal form.
Using your answers to question 1(b) and question 2(b), explain how to find the number of non-repeating decimal places and the repeat length.